Example 1: Solving a trigonometric equation on 0 to 2π
Solve sin 2x = cos x for 0 ≤ x ≤ 2π.
2 sin x cos x − cos x = 0cos x (2 sin x − 1) = 0cos x = 0givesx = π/2, 3π/2sin x = ½givesx = π/6, 5π/6
Answer: x = π/6, π/2, 5π/6, 3π/2
M2 adds four things to Core trigonometry: radian measure, the functions sec, cosec and cot, the compound and double angle formulas such as sin(A + B) = sin A cos B + cos A sin B, and the product-to-sum and sum-to-product formulas. They exist mainly to make differentiation and integration of trigonometric functions possible.
π rad = 180°1 + tan² θ = sec² θ, 1 + cot² θ = cosec² θsin(A ± B) = sin A cos B ± cos A sin Bcos(A ± B) = cos A cos B ∓ sin A sin Btan(A ± B) = (tan A ± tan B) / (1 ∓ tan A tan B)sin 2A = 2 sin A cos A, cos 2A = cos² A − sin² A = 1 − 2 sin² A = 2 cos² A − 1sin² A = ½(1 − cos 2A), cos² A = ½(1 + cos 2A)2 sin A cos B = sin(A + B) + sin(A − B), 2 cos A cos B = cos(A + B) + cos(A − B)sin A + sin B = 2 sin((A + B)/2) cos((A − B)/2), cos A + cos B = 2 cos((A + B)/2) cos((A − B)/2)Solve sin 2x = cos x for 0 ≤ x ≤ 2π.
2 sin x cos x − cos x = 0cos x (2 sin x − 1) = 0cos x = 0 gives x = π/2, 3π/2sin x = ½ gives x = π/6, 5π/6Answer: x = π/6, π/2, 5π/6, 3π/2
Prove that (sin 3x + sin x) / (cos 3x + cos x) = tan 2x.
sin 3x + sin x = 2 sin 2x cos xcos 3x + cos x = 2 cos 2x cos x= (2 sin 2x cos x) / (2 cos 2x cos x) = sin 2x / cos 2x= tan 2x = R.H.S.Answer: Proved.
cos x throws away the solutions π/2 and 3π/2. Move everything to one side and factorise instead.a sin x + b cos x as R sin(x + α) is not in the M2 syllabus, and neither are general solutions outside 0 to 2π.How to study: Click any question below to instantly load it on the coordinate grid and check your steps.