Binomial vs Poisson (DSE M1): Which Distribution Should You Use?

Use a binomial distribution when you count successes in a fixed number of trials. Use a Poisson distribution when you count events at an average rate over an interval, with no fixed number of trials. Use a normal distribution for a measured quantity such as mass or time. Long questions often feed the answer from one into another.

Solve Binomial or Poisson? Choosing the Distribution questions with AI
B(n, 2.5/n) (blue bars) against Po(2.5) (red points). As n grows with the mean fixed at 2.5, the binomial bars settle onto the Poisson values. Try it yourself →

Which Distribution? A Quick Chooser

"n trials, each with probability p"Binomial B(n, p)
"on average r per hour / per page / per km"Poisson Po(λ), with λ scaled to the interval
"mass / length / time is normally distributed"Normal N(μ, σ²)
Clue from datavariance < mean: binomial; variance ≈ mean: Poisson

How Section B Combines Distributions

A typical long question has two layers:

  1. Inner layer: find the probability p that one unit (a page, a day, a bottle) has some property, using a Poisson or normal distribution.
  2. Outer layer: take n such units. The number with the property is B(n, p), using the p from the inner layer.

A third part may then add a conditional probability. Write down, for each part, what is being counted and out of how many; that alone usually tells you the distribution.

Worked Examples — Binomial or Poisson? Choosing the Distribution

Example 1: A Poisson probability used inside a binomial

The number of typing errors on a page follows a Poisson distribution with mean 0.5. (a) Find the probability that a page has no errors. (b) Find the probability that exactly 8 pages out of 10 have no errors.

  1. (a) X ~ Po(0.5): P(X = 0) = e−0.5 = 0.6065
  2. (b) Let Y be the number of error-free pages: Y ~ B(10, e−0.5)
  3. P(Y = 8) = C(10, 8)(e−0.5)⁸(1 − e−0.5)²
  4. = 45 × e−4 × (0.39347)² = 0.1276

Answer: (a) 0.6065; (b) 0.1276

Example 2: A fixed number of trials means binomial

Each item produced is defective with probability 0.05, independently. Find the probability that a box of 20 items contains at most 1 defective item.

  1. 20 trials, constant probability: X ~ B(20, 0.05)
  2. P(X ≤ 1) = (0.95)²⁰ + 20(0.05)(0.95)¹⁹
  3. = 0.3585 + 0.3774 = 0.7358

Answer: 0.7358

💡 Exam Traps & Secrets

⚠️ Keep full accuracy between layersUse the unrounded inner probability (e−0.5, not 0.61) in the outer binomial. Rounding early can change the fourth decimal place of the final answer.
⚠️ An average rate is not a number of trials"On average 3 faults per metre" has no n, so it is Poisson. "3 of the 50 items" has a fixed n = 50, so it is binomial.

✏️ Self-Test: Quick Interactive Practice

How to study: Click any question below to instantly load it on the coordinate grid and check your steps.

(Poisson inside binomial)Customers arrive at an average of 2 per minute. Find the probability that in exactly 3 of the next 5 minutes, no customer arrives.
(Normal inside binomial)The mass of a packet is normally distributed with mean 500 g and standard deviation 4 g. Find the probability that exactly 2 of 6 packets weigh less than 495 g.
(Mean versus variance)A sample has mean 3.1 and variance 3.0. Is a binomial or a Poisson model more suitable? Explain.

Frequently Asked Questions

Related Topics

The Binomial DistributionThe Poisson DistributionApplications of the Normal DistributionCommon Mistakes in M1DSE M1: all topicsDSE M1 formula sheetM1 vs M2DSE M2 notesHKDSE Math: all topics
Try a Binomial or Poisson? Choosing the Distribution DSE Practice Question