HKDSE Trigonometry: Sine Rule, Cosine Rule & Bearings

For a triangle with sides a, b, c opposite angles A, B, C, the sine rule is a / sin A = b / sin B = c / sin C and the cosine rule is a² = b² + c² − 2bc cos A. Use the sine rule when you know a side and its opposite angle; use the cosine rule for two sides and the included angle, or for three sides. The area is ½ab sin C.

Solve More about Trigonometry questions with AIPractise 255 DSE-style questions
AB = 8 cm and AC = 5 cm stay fixed while ∠A opens from 20° to 160°. The red side BC follows the cosine rule, and the area ½ × 8 × 5 × sin A is largest at 90°. Try it yourself →

Trigonometry Formulas for HKDSE

Sine rulea / sin A = b / sin B = c / sin C
Cosine rule (side)a² = b² + c² − 2bc cos A
Cosine rule (angle)cos A = (b² + c² − a²) / (2bc)
Area of a triangle½ab sin C; Heron's formula √(s(s − a)(s − b)(s − c)), s = (a + b + c)/2
Identitiessin²θ + cos²θ = 1, tan θ = sin θ / cos θ
Obtuse anglessin(180° − θ) = sin θ, cos(180° − θ) = −cos θ
BearingsTrue bearing: clockwise from north, e.g. 030°; compass bearing: e.g. N30°E

Sine Rule or Cosine Rule? How to Choose

  • Two angles and a side (AAS or ASA): sine rule.
  • Two sides and a non-included angle (SSA): sine rule, then check the ambiguous case.
  • Two sides and the included angle (SAS): cosine rule for the third side.
  • Three sides (SSS): cosine rule in the form cos A = (b² + c² − a²) / (2bc).

For problems in solids, such as the angle between a line and a plane, see 3D trigonometry.

True Bearing vs Compass Bearing

A true bearing is measured clockwise from north and written with three digits, such as 045°. A compass bearing starts from north or south and turns towards east or west.

  • N30°E = 030°
  • S40°E = 180° − 40° = 140°
  • S25°W = 180° + 25° = 205°
  • N70°W = 360° − 70° = 290°

"The bearing of A from B" is measured at B. Bearings in opposite directions differ by 180°.

The Core Concept

How to Solve Any Triangle: When a triangle does not have a 90° angle, we cannot use standard SOH-CAH-TOA. Instead, we must use the Sine Rule or Cosine Rule. Choosing the right tool depends entirely on what information the question gives you.

DSE More about Trigonometry Cheat Sheet — 4 Key Topics

Scan this compact reference table to review every essential concept, step, and shortcut in under 10 seconds.

TopicKey Concept & StepsExam Shortcuts & Tips
1. Sine Rulea / sin A = b / sin B = c / sin C• AAS (2 angles, 1 side)
• ASA (2 angles, included side)
• SSA (2 sides, non-included angle)
Watch out for SSA:
This is the only case that can trigger the "ambiguous case" (2 possible triangles).
2. Cosine Rule• To find a side:
a² = b² + c² − 2bc cos A
• To find an angle:
cos A = (b² + c² − a²) / (2bc)
• SAS (2 sides, included angle)
• SSS (All 3 sides known)
Use the angle form to check if an angle is obtuse:
• If cos A > 0 ⟹ A is acute.
• If cos A < 0 ⟹ A is obtuse.
3. Area of TriangleArea = ½ ab sin C• SAS (2 sides and their included angle)
The angle C must be the angle pinched between sides a and b.
4. Bearings• True Bearing: Measured clockwise from North (000° to 360°).
• Compass Bearing: e.g., N30°E or S45°W.
Draw a mini coordinate cross (North-South-East-West) at the "FROM" point.

Worked Examples — More about Trigonometry

Example 1: Cosine rule and the area of a triangle

In △ABC, AB = 8 cm, AC = 5 cm and ∠A = 60°. Find BC and the area of △ABC.

  1. Two sides and the included angle are known, so use the cosine rule: BC² = 8² + 5² − 2(8)(5) cos 60°.
  2. BC² = 64 + 25 − 40 = 49, so BC = 7 cm.
  3. Area = ½ × 8 × 5 × sin 60° = 20 × (√3/2) = 10√3 ≈ 17.3 cm².

Answer: BC = 7 cm; area = 10√3 ≈ 17.3 cm².

Example 2: Bearings with Pythagoras' theorem

A ship sails 30 km from P to Q on a bearing of 060°, then 40 km from Q to R on a bearing of 150°. Find the distance PR and the bearing of R from P.

  1. At Q, the bearing back to P is 060° + 180° = 240°.
  2. So ∠PQR = 240° − 150° = 90°.
  3. PR = √(30² + 40²) = 50 km.
  4. tan ∠QPR = 40/30, so ∠QPR ≈ 53.1°. The bearing of R from P is 060° + 53.1° = 113.1°.

Answer: PR = 50 km; the bearing of R from P is about 113.1° (S66.9°E).

💡 Exam Traps & Secrets

⚠️ The Ambiguous Case (SSA) TrapWhen using the Sine Rule with Side-Side-Angle (SSA), you must check for the ambiguous case if the side opposite to the given angle (a) is shorter than the adjacent side (b) (a < b):
1. Solve for the acute angle: sin B = b sin A / a ⟹ B₁
2. Find the possible obtuse angle: B₂ = 180° − B₁
3. Test if B₂ is valid: If A + B₂ < 180°, then two distinct triangles exist, and both answers are correct!
⚠️ Bearings: "Of" vs. "From" TrapOne of the most common mistakes in Paper 1 is drawing the bearing angle from the wrong vertex. "The bearing of A from B is 120°" means you must draw your North arrow and measure the angle starting at point B, not point A.
⚠️ Angles of Elevation & DepressionBoth angles of elevation and depression are measured from the horizontal line of sight. A common mistake is measuring the angle of depression from the vertical wall/cliff instead of the horizontal.

✏️ Self-Test: Quick Interactive Practice

How to study: Click any question below to instantly load it on the coordinate grid and check your steps.

(Sine Rule SSA — Ambiguous Case)In ΔABC, AB = 7, BC = 9, and ∠BAC = 50°. Find all possible lengths of AC.
(Cosine Rule SSS angle form)In ΔPQR, PQ = 5, QR = 8, and PR = 6. Find ∠PQR.
(Multi-step 2D applications)From a point A on level ground, the angle of elevation of the top of a tower is 35°. Walking 20 m horizontally closer to the tower to point B, the angle of elevation becomes 60°. Find the height of the tower.

More about Trigonometry Exercises: DSE-Style Practice

DSE-style practice sets from the SketchMath question bank, with solutions for every MC and long question.

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