More about Equations

Master linear-quadratic simultaneous equations, unmask hidden quadratic equations in disguise, and learn how to systematically check your roots to avoid losing easy marks.

Solve More about Equations questions with AIPractise 163 DSE-style questions

Click the graph to explore it interactively →

The Core Concept

The Power of Substitution: Solving complex equations is all about unmasking the underlying structure. When solving a linear-quadratic system, we substitute the linear "clue" to reduce two variables into a single quadratic equation. When solving equations in disguise, we use the "Let u = …" substitution trick to transform fractional, exponential, logarithmic, or trigonometric terms into a standard quadratic form (au² + bu + c = 0).

DSE More about Equations Cheat Sheet — 5 Key Topics

Scan this compact reference table to review every essential concept, step, and shortcut in under 10 seconds.

TopicKey Concept & StepsExam Shortcuts & Tips
1. Linear-QuadraticMake y (or x) the subject of the linear equation and substitute it into the quadratic equation:
ax² + bx + c = 0
Intersection of a straight line and a curve (parabola or circle).
Do not plug x back into the quadratic:
Always substitute solved x values back into the linear equation to find y to avoid pairing errors.
2. FractionalMultiply the entire equation by the LCM of the denominators to clear the fractions.Analyzing rational curves.
Always check your denominators:
Any solution that makes a denominator equal to 0 must be rejected.
3. ExponentialLet u = aˣ to transform:
p(a²ˣ) + q(aˣ) + r = 0 ⟹ pu² + qu + r = 0
Analyzing rapid growth curves.
Reject negative u values:
Since aˣ > 0 for all real x, any negative solution (e.g., 2ˣ = −1) has no real solution.
4. LogarithmicCondense log terms using laws first:
log M + log N = log(MN)
If log M = log N ⟹ M = N
Analyzing logarithmic curves.
Verify the domain strictly:
The argument of any log must be strictly positive. Reject any roots that make an argument ≤ 0.
5. TrigonometricLet u = sin θ (or cos θ) to transform:
pu² + qu + r = 0
Analyzing repeating wave curves.
Reject u outside [−1, 1]:
Since −1 ≤ sin θ ≤ 1 and −1 ≤ cos θ ≤ 1, reject any u value outside this range, then solve for θ.

💡 Exam Traps & Secrets

⚠️ The Linear-Quadratic Pairing TrapWhen you solve a linear-quadratic system, you will obtain two values for x (e.g., x = 2 or x = −1). You must plug these values back into the linear equation to find the corresponding y values.
The Trap: If you substitute them into the quadratic equation, you will generate extra, incorrect coordinate pairs and lose the final accuracy marks.
⚠️ The Logarithmic Domain CheckWhen you solve a logarithmic equation, you must check your final solutions against the original log arguments.
Example: If you solve log(x − 2) + log(x + 1) = log 10 and obtain x = 4 or x = −3:
At x = 4 ⟹ log(4 − 2) = log(2) (valid).
At x = −3 ⟹ log(−3 − 2) = log(−5) (invalid!). You must reject the extraneous root x = −3.
⚠️ The "Does Not Exist" / Tangency ConditionIf a question asks for the condition where a line and a curve touch at exactly one point (or are tangent), substitute to form a quadratic and set the discriminant to zero:
Δ = b² − 4ac = 0
⚠️ Word Problem Boundary ChecksWhen translating real-world problems (e.g., rectangle dimensions) into quadratic equations, check if your answers make physical sense. Dimensions, lengths, times, or counts cannot be negative. Always reject negative solutions and write a clear concluding sentence.

✏️ Self-Test: Quick Interactive Practice

How to study: Click any question below to instantly load it on the coordinate grid and check your steps.

(Linear-Quadratic substitution & coordinate pairing)Solve the simultaneous equations: y − x = 1 and y = x² − 1.
(Quadratic substitution with u = 2ˣ, rejecting negative roots)Solve the exponential equation 4ˣ − 3 · 2ˣ − 4 = 0.
(Condensing log terms, quadratic factorization, rejecting extraneous roots)Solve the logarithmic equation log(x − 2) + log(x + 1) = log 10.
(Δ = 0)Find the value(s) of k for which the line y = kx + 3 and the parabola y = x² − 2 have exactly one solution.

More about Equations Exercises: DSE-Style Practice

DSE-style practice sets from the SketchMath question bank, with solutions for every MC and long question.

More about Equations · Form 4
128 MC questions · 35 long questions

Frequently Asked Questions

Related Topics

More about PolynomialsMore about Graphs of FunctionsHKDSE Math: all topicsHKDSE Maths Formula SheetDSE Maths Practice by Form
Try a More about Equations DSE Practice Question